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(0)=5x^2-4x+4
We move all terms to the left:
(0)-(5x^2-4x+4)=0
We add all the numbers together, and all the variables
-(5x^2-4x+4)=0
We get rid of parentheses
-5x^2+4x-4=0
a = -5; b = 4; c = -4;
Δ = b2-4ac
Δ = 42-4·(-5)·(-4)
Δ = -64
Delta is less than zero, so there is no solution for the equation
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